Get the probability of toxicity for probability-of-efficacy and utility pairs

efftox_get_tox(eff, util, p, eff0, tox1)

Arguments

eff

Probability of efficacy; number between 0 and 1

util

Utility score; number

p

p-index of EffTox utility contours. Use efftox_solve_p

eff0

Efficacy probability required when toxicity is impossible; a number between 0 and 1

tox1

Toxicity probability permitted when efficacy is guaranteed; a number between 0 and 1

Value

Probability(s) of toxicity

Note

Various ways of vectorising the function are demonstrated in the examples

See also

Examples

p <- efftox_solve_p(0.5, 0.65, 0.7, 0.25) prob_tox <- efftox_get_tox(0.7, 0, p, eff0 = 0.5, tox1 = 0.65) round(prob_tox, 2) == 0.25
#> [1] TRUE
prob_tox <- efftox_get_tox(0.7, seq(-0.5, 0.25, by = 0.25), p, eff0 = 0.5, tox1 = 0.65) round(prob_tox, 2) == c(0.57, 0.41, 0.25, 0.09)
#> [1] TRUE TRUE TRUE TRUE
prob_tox <- efftox_get_tox(c(0.5, 0.7, 0.8), 0.25, p, eff0 = 0.5, tox1 = 0.65) round(prob_tox, 2) == c(NaN, 0.09, 0.22)
#> [1] NA TRUE TRUE
prob_tox <- efftox_get_tox(c(0.5, 0.7, 0.8), c(-1, 0, 1), p, eff0 = 0.5, tox1 = 0.65) round(prob_tox, 2) == c(0.63, 0.25, NaN)
#> [1] TRUE TRUE NA